At 07 20, Dana left Town H and cycled towards Town J. Nora left Town H and cycled towards Town J at 07 50. Nora's cycling speed was 2 km/h faster than Dana. At 14 20, Nora caught up with Dana. Find the cycling speed of each cyclist.
- Dana
- Nora
(a)
Duration that Nora cycled from 07 50 to 14 20
= 6
3060 = 6
12 h
Distance that Nora cycled more than Dana
= 6
12 x 2
= 13 km
However, since Dana left 30 minutes earlier than Nora and Nora caught up with Dana, it means that Dana has cycled 13 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Dana's cycling speed
= 13 ÷
12 = 13 x
21 = 26 km/h
(b)
Nora's cycling speed
= 26 + 2
= 28 km/h
Answer(s): (a) 26 km/h ; (b) 28 km/h
