At 09 30, Jane left Town X and cycled towards Town Y. Gwen left Town X and cycled towards Town Y at 09 50. Gwen's cycling speed was 3 km/h faster than Jane. At 11 30, Gwen caught up with Jane. Find the cycling speed of each cyclist.
- Jane
- Gwen
(a)
Duration that Gwen cycled from 09 50 to 11 30
= 1
4060 = 1
23 h
Distance that Gwen cycled more than Jane
= 1
23 x 3
= 5 km
However, since Jane left 20 minutes earlier than Gwen and Gwen caught up with Jane, it means that Jane has cycled 5 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Jane's cycling speed
= 5 ÷
13 = 5 x
31 = 15 km/h
(b)
Gwen's cycling speed
= 15 + 3
= 18 km/h
Answer(s): (a) 15 km/h ; (b) 18 km/h
