At 09 35, Linda left Town U and cycled towards Town V. Kimberly left Town U and cycled towards Town V at 09 55. Kimberly's cycling speed was 3 km/h faster than Linda. At 12 35, Kimberly caught up with Linda. Find the cycling speed of each cyclist.

1. Linda
2. Kimberly

(a)
Duration that Kimberly cycled from 09 55 to 12 35
= 2⁴⁰₆₀
= 2²₃ h

Distance that Kimberly cycled more than Linda
= 2²₃ x 3
= 8 km

However, since Linda left 20 minutes earlier than Kimberly and Kimberly caught up with Linda, it means that Linda has cycled 8 km in 20 min.

1 h = 60 min 
20 min = 20 ÷ 60 = ¹₃ h

Linda's cycling speed
= 8 ÷ ¹₃
= 8 x ³₁
= 24 km/h

(b)
Kimberly's cycling speed
= 24 + 3
= 27 km/h

Answer(s): (a) 24 km/h ; (b) 27 km/h