At 09 10, Tina left Town B and cycled towards Town C. Olivia left Town B and cycled towards Town C at 09 30. Olivia's cycling speed was 3 km/h faster than Tina. At 13 10, Olivia caught up with Tina. Find the cycling speed of each cyclist.
- Tina
- Olivia
(a)
Duration that Olivia cycled from 09 30 to 13 10
= 3
4060 = 3
23 h
Distance that Olivia cycled more than Tina
= 3
23 x 3
= 11 km
However, since Tina left 20 minutes earlier than Olivia and Olivia caught up with Tina, it means that Tina has cycled 11 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Tina's cycling speed
= 11 ÷
13 = 11 x
31 = 33 km/h
(b)
Olivia's cycling speed
= 33 + 3
= 36 km/h
Answer(s): (a) 33 km/h ; (b) 36 km/h
