At 08 25, Betty left Town U and cycled towards Town V. Wendy left Town U and cycled towards Town V at 08 55. Wendy's cycling speed was 10 km/h faster than Betty. At 10 25, Wendy caught up with Betty. Find the cycling speed of each cyclist.
- Betty
- Wendy
(a)
Duration that Wendy cycled from 08 55 to 10 25
= 1
3060 = 1
12 h
Distance that Wendy cycled more than Betty
= 1
12 x 10
= 15 km
However, since Betty left 30 minutes earlier than Wendy and Wendy caught up with Betty, it means that Betty has cycled 15 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Betty's cycling speed
= 15 ÷
12 = 15 x
21 = 30 km/h
(b)
Wendy's cycling speed
= 30 + 10
= 40 km/h
Answer(s): (a) 30 km/h ; (b) 40 km/h
