At 08 25, Joelle left Town Y and cycled towards Town Z. Raeann left Town Y and cycled towards Town Z at 08 55. Raeann's cycling speed was 4 km/h faster than Joelle. At 12 25, Raeann caught up with Joelle. Find the cycling speed of each cyclist.

1. Joelle
2. Raeann

(a)
Duration that Raeann cycled from 08 55 to 12 25
= 3³⁰₆₀
= 3¹₂ h

Distance that Raeann cycled more than Joelle
= 3¹₂ x 4
= 14 km

However, since Joelle left 30 minutes earlier than Raeann and Raeann caught up with Joelle, it means that Joelle has cycled 14 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Joelle's cycling speed
= 14 ÷ ¹₂
= 14 x ²₁
= 28 km/h

(b)
Raeann's cycling speed
= 28 + 4
= 32 km/h

Answer(s): (a) 28 km/h ; (b) 32 km/h