At 08 20, Eva left Town K and cycled towards Town L. Jane left Town K and cycled towards Town L at 08 50. Jane's cycling speed was 2 km/h faster than Eva. At 14 20, Jane caught up with Eva. Find the cycling speed of each cyclist.
- Eva
- Jane
(a)
Duration that Jane cycled from 08 50 to 14 20
= 5
3060 = 5
12 h
Distance that Jane cycled more than Eva
= 5
12 x 2
= 11 km
However, since Eva left 30 minutes earlier than Jane and Jane caught up with Eva, it means that Eva has cycled 11 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Eva's cycling speed
= 11 ÷
12 = 11 x
21 = 22 km/h
(b)
Jane's cycling speed
= 22 + 2
= 24 km/h
Answer(s): (a) 22 km/h ; (b) 24 km/h
