At 07 20, Min left Town E and cycled towards Town F. Raeann left Town E and cycled towards Town F at 07 50. Raeann's cycling speed was 6 km/h faster than Min. At 10 20, Raeann caught up with Min. Find the cycling speed of each cyclist.
- Min
- Raeann
(a)
Duration that Raeann cycled from 07 50 to 10 20
= 2
3060 = 2
12 h
Distance that Raeann cycled more than Min
= 2
12 x 6
= 15 km
However, since Min left 30 minutes earlier than Raeann and Raeann caught up with Min, it means that Min has cycled 15 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Min's cycling speed
= 15 ÷
12 = 15 x
21 = 30 km/h
(b)
Raeann's cycling speed
= 30 + 6
= 36 km/h
Answer(s): (a) 30 km/h ; (b) 36 km/h
