At 09 10, Gem left Town K and cycled towards Town L. Jade left Town K and cycled towards Town L at 09 25. Jade's cycling speed was 4 km/h faster than Gem. At 11 10, Jade caught up with Gem. Find the cycling speed of each cyclist.
- Gem
- Jade
(a)
Duration that Jade cycled from 09 25 to 11 10
= 1
4560 = 1
34 h
Distance that Jade cycled more than Gem
= 1
34 x 4
= 7 km
However, since Gem left 15 minutes earlier than Jade and Jade caught up with Gem, it means that Gem has cycled 7 km in 15 min.
1 h = 60 min
15 min = 15 ÷ 60 =
14 h
Gem's cycling speed
= 7 ÷
14 = 7 x
41 = 28 km/h
(b)
Jade's cycling speed
= 28 + 4
= 32 km/h
Answer(s): (a) 28 km/h ; (b) 32 km/h
