At 08 25, Barbara left Town S and cycled towards Town T. Raeann left Town S and cycled towards Town T at 08 55. Raeann's cycling speed was 2 km/h faster than Barbara. At 11 25, Raeann caught up with Barbara. Find the cycling speed of each cyclist.

1. Barbara
2. Raeann

(a)
Duration that Raeann cycled from 08 55 to 11 25
= 2³⁰₆₀
= 2¹₂ h

Distance that Raeann cycled more than Barbara
= 2¹₂ x 2
= 5 km

However, since Barbara left 30 minutes earlier than Raeann and Raeann caught up with Barbara, it means that Barbara has cycled 5 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Barbara's cycling speed
= 5 ÷ ¹₂
= 5 x ²₁
= 10 km/h

(b)
Raeann's cycling speed
= 10 + 2
= 12 km/h

Answer(s): (a) 10 km/h ; (b) 12 km/h