At 08 15, Yoko left Town F and cycled towards Town G. Jean left Town F and cycled towards Town G at 08 55. Jean's cycling speed was 3 km/h faster than Yoko. At 12 15, Jean caught up with Yoko. Find the cycling speed of each cyclist.
- Yoko
- Jean
(a)
Duration that Jean cycled from 08 55 to 12 15
= 3
2060 = 3
13 h
Distance that Jean cycled more than Yoko
= 3
13 x 3
= 10 km
However, since Yoko left 40 minutes earlier than Jean and Jean caught up with Yoko, it means that Yoko has cycled 10 km in 40 min.
1 h = 60 min
40 min = 40 ÷ 60 =
23 h
Yoko's cycling speed
= 10 ÷
23 = 10 x
32 = 15 km/h
(b)
Jean's cycling speed
= 15 + 3
= 18 km/h
Answer(s): (a) 15 km/h ; (b) 18 km/h
