At 07 25, Jen left Town N and cycled towards Town P. Shiyun left Town N and cycled towards Town P at 07 45. Shiyun's cycling speed was 3 km/h faster than Jen. At 10 25, Shiyun caught up with Jen. Find the cycling speed of each cyclist.
- Jen
- Shiyun
(a)
Duration that Shiyun cycled from 07 45 to 10 25
= 2
4060 = 2
23 h
Distance that Shiyun cycled more than Jen
= 2
23 x 3
= 8 km
However, since Jen left 20 minutes earlier than Shiyun and Shiyun caught up with Jen, it means that Jen has cycled 8 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Jen's cycling speed
= 8 ÷
13 = 8 x
31 = 24 km/h
(b)
Shiyun's cycling speed
= 24 + 3
= 27 km/h
Answer(s): (a) 24 km/h ; (b) 27 km/h
