At 07 15, Kimberly left Town P and cycled towards Town Q. Tammy left Town P and cycled towards Town Q at 07 45. Tammy's cycling speed was 2 km/h faster than Kimberly. At 10 15, Tammy caught up with Kimberly. Find the cycling speed of each cyclist.

1. Kimberly
2. Tammy

(a)
Duration that Tammy cycled from 07 45 to 10 15
= 2³⁰₆₀
= 2¹₂ h

Distance that Tammy cycled more than Kimberly
= 2¹₂ x 2
= 5 km

However, since Kimberly left 30 minutes earlier than Tammy and Tammy caught up with Kimberly, it means that Kimberly has cycled 5 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Kimberly's cycling speed
= 5 ÷ ¹₂
= 5 x ²₁
= 10 km/h

(b)
Tammy's cycling speed
= 10 + 2
= 12 km/h

Answer(s): (a) 10 km/h ; (b) 12 km/h