At 09 10, Jade left Town A and cycled towards Town B. Shiyun left Town A and cycled towards Town B at 09 25. Shiyun's cycling speed was 4 km/h faster than Jade. At 11 10, Shiyun caught up with Jade. Find the cycling speed of each cyclist.
- Jade
- Shiyun
(a)
Duration that Shiyun cycled from 09 25 to 11 10
= 1
4560 = 1
34 h
Distance that Shiyun cycled more than Jade
= 1
34 x 4
= 7 km
However, since Jade left 15 minutes earlier than Shiyun and Shiyun caught up with Jade, it means that Jade has cycled 7 km in 15 min.
1 h = 60 min
15 min = 15 ÷ 60 =
14 h
Jade's cycling speed
= 7 ÷
14 = 7 x
41 = 28 km/h
(b)
Shiyun's cycling speed
= 28 + 4
= 32 km/h
Answer(s): (a) 28 km/h ; (b) 32 km/h
