At 08 10, Marion left Town R and cycled towards Town S. Hazel left Town R and cycled towards Town S at 08 40. Hazel's cycling speed was 4 km/h faster than Marion. At 11 10, Hazel caught up with Marion. Find the cycling speed of each cyclist.

1. Marion
2. Hazel

(a)
Duration that Hazel cycled from 08 40 to 11 10
= 2³⁰₆₀
= 2¹₂ h

Distance that Hazel cycled more than Marion
= 2¹₂ x 4
= 10 km

However, since Marion left 30 minutes earlier than Hazel and Hazel caught up with Marion, it means that Marion has cycled 10 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Marion's cycling speed
= 10 ÷ ¹₂
= 10 x ²₁
= 20 km/h

(b)
Hazel's cycling speed
= 20 + 4
= 24 km/h

Answer(s): (a) 20 km/h ; (b) 24 km/h