At 08 10, Shiyun left Town S and cycled towards Town T. Ivory left Town S and cycled towards Town T at 08 40. Ivory's cycling speed was 2 km/h faster than Shiyun. At 14 10, Ivory caught up with Shiyun. Find the cycling speed of each cyclist.

1. Shiyun
2. Ivory

(a)
Duration that Ivory cycled from 08 40 to 14 10
= 5³⁰₆₀
= 5¹₂ h

Distance that Ivory cycled more than Shiyun
= 5¹₂ x 2
= 11 km

However, since Shiyun left 30 minutes earlier than Ivory and Ivory caught up with Shiyun, it means that Shiyun has cycled 11 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Shiyun's cycling speed
= 11 ÷ ¹₂
= 11 x ²₁
= 22 km/h

(b)
Ivory's cycling speed
= 22 + 2
= 24 km/h

Answer(s): (a) 22 km/h ; (b) 24 km/h