At 07 10, Min left Town L and cycled towards Town M. Barbara left Town L and cycled towards Town M at 07 30. Barbara's cycling speed was 3 km/h faster than Min. At 10 10, Barbara caught up with Min. Find the cycling speed of each cyclist.
- Min
- Barbara
(a)
Duration that Barbara cycled from 07 30 to 10 10
= 2
4060 = 2
23 h
Distance that Barbara cycled more than Min
= 2
23 x 3
= 8 km
However, since Min left 20 minutes earlier than Barbara and Barbara caught up with Min, it means that Min has cycled 8 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Min's cycling speed
= 8 ÷
13 = 8 x
31 = 24 km/h
(b)
Barbara's cycling speed
= 24 + 3
= 27 km/h
Answer(s): (a) 24 km/h ; (b) 27 km/h
