At 08 15, Jaslyn left Town F and cycled towards Town G. Cindy left Town F and cycled towards Town G at 08 55. Cindy's cycling speed was 6 km/h faster than Jaslyn. At 10 15, Cindy caught up with Jaslyn. Find the cycling speed of each cyclist.
- Jaslyn
- Cindy
(a)
Duration that Cindy cycled from 08 55 to 10 15
= 1
2060 = 1
13 h
Distance that Cindy cycled more than Jaslyn
= 1
13 x 6
= 8 km
However, since Jaslyn left 40 minutes earlier than Cindy and Cindy caught up with Jaslyn, it means that Jaslyn has cycled 8 km in 40 min.
1 h = 60 min
40 min = 40 ÷ 60 =
23 h
Jaslyn's cycling speed
= 8 ÷
23 = 8 x
32 = 12 km/h
(b)
Cindy's cycling speed
= 12 + 6
= 18 km/h
Answer(s): (a) 12 km/h ; (b) 18 km/h
