At 08 15, Lucy left Town D and cycled towards Town E. Gem left Town D and cycled towards Town E at 08 45. Gem's cycling speed was 2 km/h faster than Lucy. At 10 15, Gem caught up with Lucy. Find the cycling speed of each cyclist.
- Lucy
- Gem
(a)
Duration that Gem cycled from 08 45 to 10 15
= 1
3060 = 1
12 h
Distance that Gem cycled more than Lucy
= 1
12 x 2
= 3 km
However, since Lucy left 30 minutes earlier than Gem and Gem caught up with Lucy, it means that Lucy has cycled 3 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Lucy's cycling speed
= 3 ÷
12 = 3 x
21 = 6 km/h
(b)
Gem's cycling speed
= 6 + 2
= 8 km/h
Answer(s): (a) 6 km/h ; (b) 8 km/h
