At 07 15, Jen left Town S and cycled towards Town T. Shiyun left Town S and cycled towards Town T at 07 45. Shiyun's cycling speed was 2 km/h faster than Jen. At 14 15, Shiyun caught up with Jen. Find the cycling speed of each cyclist.
- Jen
- Shiyun
(a)
Duration that Shiyun cycled from 07 45 to 14 15
= 6
3060 = 6
12 h
Distance that Shiyun cycled more than Jen
= 6
12 x 2
= 13 km
However, since Jen left 30 minutes earlier than Shiyun and Shiyun caught up with Jen, it means that Jen has cycled 13 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Jen's cycling speed
= 13 ÷
12 = 13 x
21 = 26 km/h
(b)
Shiyun's cycling speed
= 26 + 2
= 28 km/h
Answer(s): (a) 26 km/h ; (b) 28 km/h
