At 07 15, Esther left Town Q and cycled towards Town R. Linda left Town Q and cycled towards Town R at 07 35. Linda's cycling speed was 3 km/h faster than Esther. At 11 15, Linda caught up with Esther. Find the cycling speed of each cyclist.

1. Esther
2. Linda

(a)
Duration that Linda cycled from 07 35 to 11 15
= 3⁴⁰₆₀
= 3²₃ h

Distance that Linda cycled more than Esther
= 3²₃ x 3
= 11 km

However, since Esther left 20 minutes earlier than Linda and Linda caught up with Esther, it means that Esther has cycled 11 km in 20 min.

1 h = 60 min 
20 min = 20 ÷ 60 = ¹₃ h

Esther's cycling speed
= 11 ÷ ¹₃
= 11 x ³₁
= 33 km/h

(b)
Linda's cycling speed
= 33 + 3
= 36 km/h

Answer(s): (a) 33 km/h ; (b) 36 km/h