At 06 10, Usha left Town N and cycled towards Town P. Shannon left Town N and cycled towards Town P at 06 55. Shannon's cycling speed was 4 km/h faster than Usha. At 12 10, Shannon caught up with Usha. Find the cycling speed of each cyclist.

1. Usha
2. Shannon

(a)
Duration that Shannon cycled from 06 55 to 12 10
= 5¹⁵₆₀
= 5¹₄ h

Distance that Shannon cycled more than Usha
= 5¹₄ x 4
= 21 km

However, since Usha left 45 minutes earlier than Shannon and Shannon caught up with Usha, it means that Usha has cycled 21 km in 45 min.

1 h = 60 min 
45 min = 45 ÷ 60 = ³₄ h

Usha's cycling speed
= 21 ÷ ³₄
= 21 x ⁴₃
= 28 km/h

(b)
Shannon's cycling speed
= 28 + 4
= 32 km/h

Answer(s): (a) 28 km/h ; (b) 32 km/h