At 07 30, Julie left Town C and cycled towards Town D. Min left Town C and cycled towards Town D at 07 50. Min's cycling speed was 3 km/h faster than Julie. At 10 30, Min caught up with Julie. Find the cycling speed of each cyclist.
- Julie
- Min
(a)
Duration that Min cycled from 07 50 to 10 30
= 2
4060 = 2
23 h
Distance that Min cycled more than Julie
= 2
23 x 3
= 8 km
However, since Julie left 20 minutes earlier than Min and Min caught up with Julie, it means that Julie has cycled 8 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Julie's cycling speed
= 8 ÷
13 = 8 x
31 = 24 km/h
(b)
Min's cycling speed
= 24 + 3
= 27 km/h
Answer(s): (a) 24 km/h ; (b) 27 km/h
