At 08 15, Jaslyn left Town U and cycled towards Town V. Gillian left Town U and cycled towards Town V at 08 45. Gillian's cycling speed was 2 km/h faster than Jaslyn. At 15 15, Gillian caught up with Jaslyn. Find the cycling speed of each cyclist.

1. Jaslyn
2. Gillian

(a)
Duration that Gillian cycled from 08 45 to 15 15
= 6³⁰₆₀
= 6¹₂ h

Distance that Gillian cycled more than Jaslyn
= 6¹₂ x 2
= 13 km

However, since Jaslyn left 30 minutes earlier than Gillian and Gillian caught up with Jaslyn, it means that Jaslyn has cycled 13 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Jaslyn's cycling speed
= 13 ÷ ¹₂
= 13 x ²₁
= 26 km/h

(b)
Gillian's cycling speed
= 26 + 2
= 28 km/h

Answer(s): (a) 26 km/h ; (b) 28 km/h