At 06 20, Dana left Town N and cycled towards Town P. Abi left Town N and cycled towards Town P at 06 50. Abi's cycling speed was 2 km/h faster than Dana. At 11 20, Abi caught up with Dana. Find the cycling speed of each cyclist.
- Dana
- Abi
(a)
Duration that Abi cycled from 06 50 to 11 20
= 4
3060 = 4
12 h
Distance that Abi cycled more than Dana
= 4
12 x 2
= 9 km
However, since Dana left 30 minutes earlier than Abi and Abi caught up with Dana, it means that Dana has cycled 9 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Dana's cycling speed
= 9 ÷
12 = 9 x
21 = 18 km/h
(b)
Abi's cycling speed
= 18 + 2
= 20 km/h
Answer(s): (a) 18 km/h ; (b) 20 km/h
