At 08 15, Raeann left Town S and cycled towards Town T. Betty left Town S and cycled towards Town T at 08 55. Betty's cycling speed was 3 km/h faster than Raeann. At 14 15, Betty caught up with Raeann. Find the cycling speed of each cyclist.

1. Raeann
2. Betty

(a)
Duration that Betty cycled from 08 55 to 14 15
= 5²⁰₆₀
= 5¹₃ h

Distance that Betty cycled more than Raeann
= 5¹₃ x 3
= 16 km

However, since Raeann left 40 minutes earlier than Betty and Betty caught up with Raeann, it means that Raeann has cycled 16 km in 40 min.

1 h = 60 min 
40 min = 40 ÷ 60 = ²₃ h

Raeann's cycling speed
= 16 ÷ ²₃
= 16 x ³₂
= 24 km/h

(b)
Betty's cycling speed
= 24 + 3
= 27 km/h

Answer(s): (a) 24 km/h ; (b) 27 km/h