At 05 25, Min left Town U and cycled towards Town V. Jaslyn left Town U and cycled towards Town V at 05 55. Jaslyn's cycling speed was 2 km/h faster than Min. At 14 25, Jaslyn caught up with Min. Find the cycling speed of each cyclist.
- Min
- Jaslyn
(a)
Duration that Jaslyn cycled from 05 55 to 14 25
= 8
3060 = 8
12 h
Distance that Jaslyn cycled more than Min
= 8
12 x 2
= 17 km
However, since Min left 30 minutes earlier than Jaslyn and Jaslyn caught up with Min, it means that Min has cycled 17 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Min's cycling speed
= 17 ÷
12 = 17 x
21 = 34 km/h
(b)
Jaslyn's cycling speed
= 34 + 2
= 36 km/h
Answer(s): (a) 34 km/h ; (b) 36 km/h
