At 08 15, Kathy left Town N and cycled towards Town P. Marion left Town N and cycled towards Town P at 08 45. Marion's cycling speed was 4 km/h faster than Kathy. At 12 15, Marion caught up with Kathy. Find the cycling speed of each cyclist.

1. Kathy
2. Marion

(a)
Duration that Marion cycled from 08 45 to 12 15
= 3³⁰₆₀
= 3¹₂ h

Distance that Marion cycled more than Kathy
= 3¹₂ x 4
= 14 km

However, since Kathy left 30 minutes earlier than Marion and Marion caught up with Kathy, it means that Kathy has cycled 14 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Kathy's cycling speed
= 14 ÷ ¹₂
= 14 x ²₁
= 28 km/h

(b)
Marion's cycling speed
= 28 + 4
= 32 km/h

Answer(s): (a) 28 km/h ; (b) 32 km/h