At 09 35, Yoko left Town G and cycled towards Town H. Kimberly left Town G and cycled towards Town H at 09 55. Kimberly's cycling speed was 3 km/h faster than Yoko. At 12 35, Kimberly caught up with Yoko. Find the cycling speed of each cyclist.

1. Yoko
2. Kimberly

(a)
Duration that Kimberly cycled from 09 55 to 12 35
= 2⁴⁰₆₀
= 2²₃ h

Distance that Kimberly cycled more than Yoko
= 2²₃ x 3
= 8 km

However, since Yoko left 20 minutes earlier than Kimberly and Kimberly caught up with Yoko, it means that Yoko has cycled 8 km in 20 min.

1 h = 60 min 
20 min = 20 ÷ 60 = ¹₃ h

Yoko's cycling speed
= 8 ÷ ¹₃
= 8 x ³₁
= 24 km/h

(b)
Kimberly's cycling speed
= 24 + 3
= 27 km/h

Answer(s): (a) 24 km/h ; (b) 27 km/h