At 07 10, Wendy left Town B and cycled towards Town C. Cathy left Town B and cycled towards Town C at 07 40. Cathy's cycling speed was 2 km/h faster than Wendy. At 11 10, Cathy caught up with Wendy. Find the cycling speed of each cyclist.
- Wendy
- Cathy
(a)
Duration that Cathy cycled from 07 40 to 11 10
= 3
3060 = 3
12 h
Distance that Cathy cycled more than Wendy
= 3
12 x 2
= 7 km
However, since Wendy left 30 minutes earlier than Cathy and Cathy caught up with Wendy, it means that Wendy has cycled 7 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Wendy's cycling speed
= 7 ÷
12 = 7 x
21 = 14 km/h
(b)
Cathy's cycling speed
= 14 + 2
= 16 km/h
Answer(s): (a) 14 km/h ; (b) 16 km/h
