At 09 10, Esther left Town B and cycled towards Town C. Emma left Town B and cycled towards Town C at 09 40. Emma's cycling speed was 8 km/h faster than Esther. At 11 10, Emma caught up with Esther. Find the cycling speed of each cyclist.
- Esther
- Emma
(a)
Duration that Emma cycled from 09 40 to 11 10
= 1
3060 = 1
12 h
Distance that Emma cycled more than Esther
= 1
12 x 8
= 12 km
However, since Esther left 30 minutes earlier than Emma and Emma caught up with Esther, it means that Esther has cycled 12 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Esther's cycling speed
= 12 ÷
12 = 12 x
21 = 24 km/h
(b)
Emma's cycling speed
= 24 + 8
= 32 km/h
Answer(s): (a) 24 km/h ; (b) 32 km/h
