At 08 15, Esther left Town A and cycled towards Town B. Usha left Town A and cycled towards Town B at 08 45. Usha's cycling speed was 2 km/h faster than Esther. At 11 15, Usha caught up with Esther. Find the cycling speed of each cyclist.
- Esther
- Usha
(a)
Duration that Usha cycled from 08 45 to 11 15
= 2
3060 = 2
12 h
Distance that Usha cycled more than Esther
= 2
12 x 2
= 5 km
However, since Esther left 30 minutes earlier than Usha and Usha caught up with Esther, it means that Esther has cycled 5 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Esther's cycling speed
= 5 ÷
12 = 5 x
21 = 10 km/h
(b)
Usha's cycling speed
= 10 + 2
= 12 km/h
Answer(s): (a) 10 km/h ; (b) 12 km/h
