At 06 10, Anna left Town B and cycled towards Town C. Xuan left Town B and cycled towards Town C at 06 40. Xuan's cycling speed was 4 km/h faster than Anna. At 11 10, Xuan caught up with Anna. Find the cycling speed of each cyclist.
- Anna
- Xuan
(a)
Duration that Xuan cycled from 06 40 to 11 10
= 4
3060 = 4
12 h
Distance that Xuan cycled more than Anna
= 4
12 x 4
= 18 km
However, since Anna left 30 minutes earlier than Xuan and Xuan caught up with Anna, it means that Anna has cycled 18 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Anna's cycling speed
= 18 ÷
12 = 18 x
21 = 36 km/h
(b)
Xuan's cycling speed
= 36 + 4
= 40 km/h
Answer(s): (a) 36 km/h ; (b) 40 km/h
