At 07 30, Jaslyn left Town A and cycled towards Town B. Natalie left Town A and cycled towards Town B at 07 50. Natalie's cycling speed was 3 km/h faster than Jaslyn. At 11 30, Natalie caught up with Jaslyn. Find the cycling speed of each cyclist.

1. Jaslyn
2. Natalie

(a)
Duration that Natalie cycled from 07 50 to 11 30
= 3⁴⁰₆₀
= 3²₃ h

Distance that Natalie cycled more than Jaslyn
= 3²₃ x 3
= 11 km

However, since Jaslyn left 20 minutes earlier than Natalie and Natalie caught up with Jaslyn, it means that Jaslyn has cycled 11 km in 20 min.

1 h = 60 min 
20 min = 20 ÷ 60 = ¹₃ h

Jaslyn's cycling speed
= 11 ÷ ¹₃
= 11 x ³₁
= 33 km/h

(b)
Natalie's cycling speed
= 33 + 3
= 36 km/h

Answer(s): (a) 33 km/h ; (b) 36 km/h