At 09 20, Olivia left Town C and cycled towards Town D. Kimberly left Town C and cycled towards Town D at 09 50. Kimberly's cycling speed was 2 km/h faster than Olivia. At 12 20, Kimberly caught up with Olivia. Find the cycling speed of each cyclist.

1. Olivia
2. Kimberly

(a)
Duration that Kimberly cycled from 09 50 to 12 20
= 2³⁰₆₀
= 2¹₂ h

Distance that Kimberly cycled more than Olivia
= 2¹₂ x 2
= 5 km

However, since Olivia left 30 minutes earlier than Kimberly and Kimberly caught up with Olivia, it means that Olivia has cycled 5 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Olivia's cycling speed
= 5 ÷ ¹₂
= 5 x ²₁
= 10 km/h

(b)
Kimberly's cycling speed
= 10 + 2
= 12 km/h

Answer(s): (a) 10 km/h ; (b) 12 km/h