At 09 10, Jean left Town M and cycled towards Town N. Zoe left Town M and cycled towards Town N at 09 30. Zoe's cycling speed was 3 km/h faster than Jean. At 11 10, Zoe caught up with Jean. Find the cycling speed of each cyclist.
- Jean
- Zoe
(a)
Duration that Zoe cycled from 09 30 to 11 10
= 1
4060 = 1
23 h
Distance that Zoe cycled more than Jean
= 1
23 x 3
= 5 km
However, since Jean left 20 minutes earlier than Zoe and Zoe caught up with Jean, it means that Jean has cycled 5 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Jean's cycling speed
= 5 ÷
13 = 5 x
31 = 15 km/h
(b)
Zoe's cycling speed
= 15 + 3
= 18 km/h
Answer(s): (a) 15 km/h ; (b) 18 km/h
