At 09 25, Jaslyn left Town Y and cycled towards Town Z. Dana left Town Y and cycled towards Town Z at 09 55. Dana's cycling speed was 4 km/h faster than Jaslyn. At 12 25, Dana caught up with Jaslyn. Find the cycling speed of each cyclist.
- Jaslyn
- Dana
(a)
Duration that Dana cycled from 09 55 to 12 25
= 2
3060 = 2
12 h
Distance that Dana cycled more than Jaslyn
= 2
12 x 4
= 10 km
However, since Jaslyn left 30 minutes earlier than Dana and Dana caught up with Jaslyn, it means that Jaslyn has cycled 10 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Jaslyn's cycling speed
= 10 ÷
12 = 10 x
21 = 20 km/h
(b)
Dana's cycling speed
= 20 + 4
= 24 km/h
Answer(s): (a) 20 km/h ; (b) 24 km/h
