At 07 20, Erika left Town N and cycled towards Town P. Jaslyn left Town N and cycled towards Town P at 07 50. Jaslyn's cycling speed was 4 km/h faster than Erika. At 11 20, Jaslyn caught up with Erika. Find the cycling speed of each cyclist.

1. Erika
2. Jaslyn

(a)
Duration that Jaslyn cycled from 07 50 to 11 20
= 3³⁰₆₀
= 3¹₂ h

Distance that Jaslyn cycled more than Erika
= 3¹₂ x 4
= 14 km

However, since Erika left 30 minutes earlier than Jaslyn and Jaslyn caught up with Erika, it means that Erika has cycled 14 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Erika's cycling speed
= 14 ÷ ¹₂
= 14 x ²₁
= 28 km/h

(b)
Jaslyn's cycling speed
= 28 + 4
= 32 km/h

Answer(s): (a) 28 km/h ; (b) 32 km/h