At 06 15, Cindy left Town L and cycled towards Town M. Gwen left Town L and cycled towards Town M at 06 45. Gwen's cycling speed was 4 km/h faster than Cindy. At 10 15, Gwen caught up with Cindy. Find the cycling speed of each cyclist.
- Cindy
- Gwen
(a)
Duration that Gwen cycled from 06 45 to 10 15
= 3
3060 = 3
12 h
Distance that Gwen cycled more than Cindy
= 3
12 x 4
= 14 km
However, since Cindy left 30 minutes earlier than Gwen and Gwen caught up with Cindy, it means that Cindy has cycled 14 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Cindy's cycling speed
= 14 ÷
12 = 14 x
21 = 28 km/h
(b)
Gwen's cycling speed
= 28 + 4
= 32 km/h
Answer(s): (a) 28 km/h ; (b) 32 km/h
