At 09 15, Jade left Town V and cycled towards Town W. Sabrina left Town V and cycled towards Town W at 09 45. Sabrina's cycling speed was 8 km/h faster than Jade. At 11 15, Sabrina caught up with Jade. Find the cycling speed of each cyclist.

1. Jade
2. Sabrina

(a)
Duration that Sabrina cycled from 09 45 to 11 15
= 1³⁰₆₀
= 1¹₂ h

Distance that Sabrina cycled more than Jade
= 1¹₂ x 8
= 12 km

However, since Jade left 30 minutes earlier than Sabrina and Sabrina caught up with Jade, it means that Jade has cycled 12 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Jade's cycling speed
= 12 ÷ ¹₂
= 12 x ²₁
= 24 km/h

(b)
Sabrina's cycling speed
= 24 + 8
= 32 km/h

Answer(s): (a) 24 km/h ; (b) 32 km/h