At 05 25, Xuan left Town X and cycled towards Town Y. Gem left Town X and cycled towards Town Y at 05 55. Gem's cycling speed was 2 km/h faster than Xuan. At 10 25, Gem caught up with Xuan. Find the cycling speed of each cyclist.
- Xuan
- Gem
(a)
Duration that Gem cycled from 05 55 to 10 25
= 4
3060 = 4
12 h
Distance that Gem cycled more than Xuan
= 4
12 x 2
= 9 km
However, since Xuan left 30 minutes earlier than Gem and Gem caught up with Xuan, it means that Xuan has cycled 9 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Xuan's cycling speed
= 9 ÷
12 = 9 x
21 = 18 km/h
(b)
Gem's cycling speed
= 18 + 2
= 20 km/h
Answer(s): (a) 18 km/h ; (b) 20 km/h
