At 09 15, Opal left Town H and cycled towards Town J. Xuan left Town H and cycled towards Town J at 09 35. Xuan's cycling speed was 3 km/h faster than Opal. At 12 15, Xuan caught up with Opal. Find the cycling speed of each cyclist.
- Opal
- Xuan
(a)
Duration that Xuan cycled from 09 35 to 12 15
= 2
4060 = 2
23 h
Distance that Xuan cycled more than Opal
= 2
23 x 3
= 8 km
However, since Opal left 20 minutes earlier than Xuan and Xuan caught up with Opal, it means that Opal has cycled 8 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Opal's cycling speed
= 8 ÷
13 = 8 x
31 = 24 km/h
(b)
Xuan's cycling speed
= 24 + 3
= 27 km/h
Answer(s): (a) 24 km/h ; (b) 27 km/h
