At 06 25, Betty left Town Z and cycled towards Town A. Nora left Town Z and cycled towards Town A at 06 55. Nora's cycling speed was 4 km/h faster than Betty. At 11 25, Nora caught up with Betty. Find the cycling speed of each cyclist.
- Betty
- Nora
(a)
Duration that Nora cycled from 06 55 to 11 25
= 4
3060 = 4
12 h
Distance that Nora cycled more than Betty
= 4
12 x 4
= 18 km
However, since Betty left 30 minutes earlier than Nora and Nora caught up with Betty, it means that Betty has cycled 18 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Betty's cycling speed
= 18 ÷
12 = 18 x
21 = 36 km/h
(b)
Nora's cycling speed
= 36 + 4
= 40 km/h
Answer(s): (a) 36 km/h ; (b) 40 km/h
