At 08 15, Hazel left Town K and cycled towards Town L. Jade left Town K and cycled towards Town L at 08 45. Jade's cycling speed was 4 km/h faster than Hazel. At 11 15, Jade caught up with Hazel. Find the cycling speed of each cyclist.
- Hazel
- Jade
(a)
Duration that Jade cycled from 08 45 to 11 15
= 2
3060 = 2
12 h
Distance that Jade cycled more than Hazel
= 2
12 x 4
= 10 km
However, since Hazel left 30 minutes earlier than Jade and Jade caught up with Hazel, it means that Hazel has cycled 10 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Hazel's cycling speed
= 10 ÷
12 = 10 x
21 = 20 km/h
(b)
Jade's cycling speed
= 20 + 4
= 24 km/h
Answer(s): (a) 20 km/h ; (b) 24 km/h
