At 08 20, Anna left Town Z and cycled towards Town A. Jean left Town Z and cycled towards Town A at 08 50. Jean's cycling speed was 2 km/h faster than Anna. At 10 20, Jean caught up with Anna. Find the cycling speed of each cyclist.
- Anna
- Jean
(a)
Duration that Jean cycled from 08 50 to 10 20
= 1
3060 = 1
12 h
Distance that Jean cycled more than Anna
= 1
12 x 2
= 3 km
However, since Anna left 30 minutes earlier than Jean and Jean caught up with Anna, it means that Anna has cycled 3 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Anna's cycling speed
= 3 ÷
12 = 3 x
21 = 6 km/h
(b)
Jean's cycling speed
= 6 + 2
= 8 km/h
Answer(s): (a) 6 km/h ; (b) 8 km/h
