At 08 15, Penelope left Town G and cycled towards Town H. Shannon left Town G and cycled towards Town H at 08 35. Shannon's cycling speed was 3 km/h faster than Penelope. At 11 15, Shannon caught up with Penelope. Find the cycling speed of each cyclist.

1. Penelope
2. Shannon

(a)
Duration that Shannon cycled from 08 35 to 11 15
= 2⁴⁰₆₀
= 2²₃ h

Distance that Shannon cycled more than Penelope
= 2²₃ x 3
= 8 km

However, since Penelope left 20 minutes earlier than Shannon and Shannon caught up with Penelope, it means that Penelope has cycled 8 km in 20 min.

1 h = 60 min 
20 min = 20 ÷ 60 = ¹₃ h

Penelope's cycling speed
= 8 ÷ ¹₃
= 8 x ³₁
= 24 km/h

(b)
Shannon's cycling speed
= 24 + 3
= 27 km/h

Answer(s): (a) 24 km/h ; (b) 27 km/h