At 08 20, Kimberly left Town V and cycled towards Town W. Victoria left Town V and cycled towards Town W at 08 50. Victoria's cycling speed was 6 km/h faster than Kimberly. At 11 20, Victoria caught up with Kimberly. Find the cycling speed of each cyclist.

1. Kimberly
2. Victoria

(a)
Duration that Victoria cycled from 08 50 to 11 20
= 2³⁰₆₀
= 2¹₂ h

Distance that Victoria cycled more than Kimberly
= 2¹₂ x 6
= 15 km

However, since Kimberly left 30 minutes earlier than Victoria and Victoria caught up with Kimberly, it means that Kimberly has cycled 15 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Kimberly's cycling speed
= 15 ÷ ¹₂
= 15 x ²₁
= 30 km/h

(b)
Victoria's cycling speed
= 30 + 6
= 36 km/h

Answer(s): (a) 30 km/h ; (b) 36 km/h