At 08 15, Joelle left Town A and cycled towards Town B. Dana left Town A and cycled towards Town B at 08 45. Dana's cycling speed was 4 km/h faster than Joelle. At 10 15, Dana caught up with Joelle. Find the cycling speed of each cyclist.
- Joelle
- Dana
(a)
Duration that Dana cycled from 08 45 to 10 15
= 1
3060 = 1
12 h
Distance that Dana cycled more than Joelle
= 1
12 x 4
= 6 km
However, since Joelle left 30 minutes earlier than Dana and Dana caught up with Joelle, it means that Joelle has cycled 6 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Joelle's cycling speed
= 6 ÷
12 = 6 x
21 = 12 km/h
(b)
Dana's cycling speed
= 12 + 4
= 16 km/h
Answer(s): (a) 12 km/h ; (b) 16 km/h