At 08 20, Cindy left Town T and cycled towards Town U. Jane left Town T and cycled towards Town U at 08 50. Jane's cycling speed was 2 km/h faster than Cindy. At 10 20, Jane caught up with Cindy. Find the cycling speed of each cyclist.
- Cindy
- Jane
(a)
Duration that Jane cycled from 08 50 to 10 20
= 1
3060 = 1
12 h
Distance that Jane cycled more than Cindy
= 1
12 x 2
= 3 km
However, since Cindy left 30 minutes earlier than Jane and Jane caught up with Cindy, it means that Cindy has cycled 3 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Cindy's cycling speed
= 3 ÷
12 = 3 x
21 = 6 km/h
(b)
Jane's cycling speed
= 6 + 2
= 8 km/h
Answer(s): (a) 6 km/h ; (b) 8 km/h
