At 09 15, Usha left Town K and cycled towards Town L. Gem left Town K and cycled towards Town L at 09 55. Gem's cycling speed was 3 km/h faster than Usha. At 13 15, Gem caught up with Usha. Find the cycling speed of each cyclist.
- Usha
- Gem
(a)
Duration that Gem cycled from 09 55 to 13 15
= 3
2060 = 3
13 h
Distance that Gem cycled more than Usha
= 3
13 x 3
= 10 km
However, since Usha left 40 minutes earlier than Gem and Gem caught up with Usha, it means that Usha has cycled 10 km in 40 min.
1 h = 60 min
40 min = 40 ÷ 60 =
23 h
Usha's cycling speed
= 10 ÷
23 = 10 x
32 = 15 km/h
(b)
Gem's cycling speed
= 15 + 3
= 18 km/h
Answer(s): (a) 15 km/h ; (b) 18 km/h
